TL;DR — Quick Summary
Introduction to Polynomial
An algebraic expression in which the exponent of each variable is a whole number is called a polynomial.
Example: \(2x^{\frac{1}{2}}\) (not polynomial), \(2x^{-2}\) (not polynomial), \(2x^{2}\) (polynomial)
The general form of a n degree Polynomial can be written as.
Where,
- \(a_n, a_{n-1}, a_{n-2}, ….. ….. a_1, a_0 \) are are real number coefficients.
- n is a whole number (the degree of the polynomial)
- The exponent of the variable x must be either zero or a positive whole number only
Key Properties
- Since a polynomial is a function, it is used not only in mathematics but also in practical applications such as demand, supply, velocity, acceleration, cost, production, and other fields.
- Polynomials can be classified by degree: Linear (degree 1), Quadratic (degree 2), Cubic (degree 3), Quartic (degree 4), etc.
Examples: \(f(x) = x^4 – 3x^3 + 5x^2 + 4\) (4 degree polynomial), \(x^3 + 2x^2 + 3x - 6\) (3 degree polynomial
Division Theorem
Statement:
Proof
When the polynomial $f(x)$ is divided by the divisor $(x - a)$, there exist the quotient $q(x)$ and the remainder $R$. Then, according to the ordinary division method, the relation among $f(x)$, $(x - a)$, $q(x)$, and $R$ is:
$f(x) = q(x) \times (x - a) + R \quad \ldots (i)$
Substituting $x = a$ in equation $(i)$:
$f(a) = q(a) \times (a - a) + R$
$f(a) = q(a) \times 0 + R$
$\boxed{f(a) = R}$
Therefore, $R = f(a)$. Hence, proved. $\blacksquare$
Division Relation
If $f(x)$ is divided by $d(x)$ with quotient $q(x)$ and remainder $R$:
$f(x) = d(x) \times q(x) + R$
Or equivalently:
$\frac{f(x)}{d(x)} = q(x) + \frac{R}{d(x)}$
If $R = 0$, then $\frac{f(x)}{d(x)} = q(x)$, meaning $f(x)$ is exactly divisible by $d(x)$.
Rational Root Theorem
The Rational Root Theorem (sometimes called the Rational Zero Theorem) is a powerful tool in algebra. It helps you find the possible rational solutions (roots) of a polynomial equation with integer coefficients. For Class 10 students, this theorem is especially useful for solving polynomial equations of **degree 3 or higher**, which cannot be easily factored using simpler methods.
Statement
Step-by-Step Method to Find Rational Roots
1. **Identify the constant term (\(a_0\)) and the leading coefficient (\(a_n\))** of the polynomial.
2. **List all factors of the constant term.** These are the possible values for the numerator \(p\).
3. **List all factors of the leading coefficient.** These are the possible values for the denominator \(q\).
4. **Form all possible fractions \(\pm \frac{p}{q}\)** and simplify. Remove any duplicates. This gives you the complete list of **possible rational roots**.
5. **Test each possible root** by substituting it into the polynomial. You can use direct substitution or **synthetic division**. If the result is zero, you have found a root.
Chapter Discussion
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Dristi
1 week agogive me question related to these for see 2083